Web24 okt. 2024 · the value of a determines if the graph opens up/down. ∙ if a > 0 then graph opens up ⋃. ∙ if a < 0 the graph opens down ⋂. here a = − 1 ⇒ graph opens down. … WebConsequently, to determine the intervals where a function f is concave up and concave down, we look for those values of x where f″(x) = 0 or f″(x) is undefined. When we have …
Unit 4 Part 1: Graphing Quadratic Functions - lcps.org
Web15 okt. 2024 · As seen in earlier sections, the value of a can determine if the parabola opens up (a > 0) or down (a < 0). However, the values of a, b, and c also contribute to … Web27 sep. 2024 · • If a > 0 then opens up and is a minimum • I f a < 0 then opens down and is a maximum. the y- intercept = c and the vertex = (0, c) The axis of symmetry is the y- axis, that is x = 0. f(x) = -5x² + 5 is in this form with a = - 5 < 0 and c = 5. Thus the parabola opens down and is a maximum. The axis of symmetry is x = 0, vertex = (0, 5 ... tsp phishing email
Revision sheet Grade 9 Mathematics
WebYou can put this solution on YOUR website! How can I tell if a graph opens up or down by looking at the equation. For the quadratic equation: if a>0 it will open up. if a<0 it will … WebThe graph opens up if a > 0 and opens down when a < 0. For absolute value equations multiplied by a constant (for example, y = a x ),if 0 < a < 1, then the graph is … Web22 jul. 2024 · Finding the vertex by completing the square gives you the maximum value. To do that, follow these steps: Rearrange the terms in descending order. This step gives you – x2 + 10 x = MAX. Factor out the leading term. You now have –1 ( x2 – 10 x) = MAX. Complete the square. This step expands the equation to –1 ( x2 – 10 x + 25) = MAX – 25. phish 2019 tour